(3x-2)(2x^2+5x-4)=0

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Solution for (3x-2)(2x^2+5x-4)=0 equation: 


Simplifying
(3x + -2)(2x2 + 5x + -4) = 0

Reorder the terms:
(-2 + 3x)(2x2 + 5x + -4) = 0

Reorder the terms:
(-2 + 3x)(-4 + 5x + 2x2) = 0

Multiply (-2 + 3x) * (-4 + 5x + 2x2)
(-2(-4 + 5x + 2x2) + 3x * (-4 + 5x + 2x2)) = 0
((-4 * -2 + 5x * -2 + 2x2 * -2) + 3x * (-4 + 5x + 2x2)) = 0
((8 + -10x + -4x2) + 3x * (-4 + 5x + 2x2)) = 0
(8 + -10x + -4x2 + (-4 * 3x + 5x * 3x + 2x2 * 3x)) = 0
(8 + -10x + -4x2 + (-12x + 15x2 + 6x3)) = 0

Reorder the terms:
(8 + -10x + -12x + -4x2 + 15x2 + 6x3) = 0

Combine like terms: -10x + -12x = -22x
(8 + -22x + -4x2 + 15x2 + 6x3) = 0

Combine like terms: -4x2 + 15x2 = 11x2
(8 + -22x + 11x2 + 6x3) = 0

Solving
8 + -22x + 11x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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